https://file.aiquickdraw.com/mathbot/file/1725495577934rnv5z9n0.jpg

The equation in the image is:

\[
\frac{ad}{b} = \frac{3c}{n}
\]

To solve for \( n \), we can cross-multiply:

\[
ad \cdot n = 3c \cdot b
\]

Now, divide both sides by \( ad \):

\[
n = \frac{3c \cdot b}{ad}
\]

Thus, the solution for \( n \) is:

\[
n = \frac{3bc}{ad}
\]

Would you like further details or have any questions?

Here are five related questions to deepen your understanding:
1. How do you apply cross-multiplication in equations like these?
2. What is the significance of variables in equations, and how can they be substituted with values?
3. How would this solution change if \( b = 0 \)?
4. Can this equation be used in real-world problems? If so, give an example.
5. How can we verify the solution by plugging values back into the original equation?

**Tip:** Always check if any variables can be zero in your final solution to avoid undefined results (like division by zero).

Learn how to solve for n in the equation ad/b = 3c/n using cross-multiplication. This problem explores fundamental algebraic techniques to rearrange and solve for variables, suitable for students in Grades 8-10.

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