To solve for \( b \) in the equation

\[ \frac{b}{4} - 1 = 2, \]

follow these steps:

1. **Isolate the term with \( b \)**: Add 1 to both sides of the equation to get rid of the -1 on the left side.

   \[ \frac{b}{4} - 1 + 1 = 2 + 1 \]

   Simplifying this gives:

   \[ \frac{b}{4} = 3 \]

2. **Solve for \( b \)**: Multiply both sides of the equation by 4 to solve for \( b \).

   \[ 4 \cdot \frac{b}{4} = 3 \cdot 4 \]

   Simplifying this gives:

   \[ b = 12 \]

So, the solution is \( b = 12 \).

Would you like a detailed explanation or have any questions about this problem? Here are some related questions you might find helpful:

1. How would you solve \(\frac{b}{4} - 3 = 5\)?
2. What if the equation were \(\frac{b}{5} - 1 = 2\)?
3. How do you solve \(\frac{b}{4} + 1 = 2\)?
4. What is the process for solving \(\frac{b}{4} - 1 = -2\)?
5. How would the steps change for \(\frac{b}{4} - 1 = 0\)?
6. What if the variable were in the denominator, like \(\frac{4}{b} - 1 = 2\)?
7. How do you handle fractions in equations like \(\frac{b+1}{4} = 2\)?
8. Can you explain the process for solving \(\frac{2b}{4} - 1 = 2\)?

**Tip:** Always isolate the variable by performing inverse operations step by step to simplify the equation.

Learn how to solve the equation involving fractions: b/4 - 1 = 2. Follow step-by-step instructions to isolate the variable b and solve for its value. This problem covers basic algebraic concepts and is suitable for students in Grades 6-8.

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