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We are given the equation:

\[
5 = \frac{a}{-3}
\]

To solve for \(a\), we need to isolate \(a\) on one side of the equation. We can do this by multiplying both sides by \(-3\), which is the denominator of the fraction.

\[
5 \times (-3) = \frac{a}{-3} \times (-3)
\]

This simplifies to:

\[
a = -15
\]

Thus, the solution is:

\[
a = -15
\]

Would you like further explanation, or do you have any other questions?

Here are five related questions for further practice:
1. Solve for \(x\) in the equation \(4 = \frac{x}{-2}\).
2. What happens to the value of \(a\) if the equation is \(5 = \frac{a}{2}\)?
3. Solve \(7 = \frac{b}{-4}\) for \(b\).
4. How would the solution change if the equation was \(5 = \frac{a}{3}\)?
5. What is the general process for solving an equation of the form \(c = \frac{a}{b}\)?

**Tip**: When solving equations involving fractions, multiplying both sides by the denominator helps to eliminate the fraction and isolate the variable.

Learn how to solve the algebraic equation 5 = a / -3. This solution demonstrates multiplying both sides by -3 to isolate the variable a, leading to the result a = -15. Suitable for students in Grades 6-8, this explanation covers essential algebraic principles.

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