To solve for \( D \) in the equation:

\[
D(h^3 + n) = t
\]

### Step 1: Isolate \( D \) on one side of the equation.

Divide both sides of the equation by \( h^3 + n \):

\[
D = \frac{t}{h^3 + n}
\]

### Final solution:

\[
D = \frac{t}{h^3 + n}
\]

This is the expression for \( D \) in terms of \( t \), \( h \), and \( n \).

Would you like a more detailed breakdown, or do you have any questions?

Here are some related questions for further practice:

1. If \( t = 27 \), \( h = 2 \), and \( n = 3 \), what is the value of \( D \)?
2. Solve \( D(h^2 + m) = x \) for \( D \).
3. If \( h = 0 \) in the original equation, what happens to the expression for \( D \)?
4. What happens to \( D \) as \( h \to \infty \)?
5. How does the equation change if \( n \) is a function of \( h \)?

**Tip:** When solving for a variable, always look for common terms that can be isolated or factored out.

Learn how to solve the algebraic equation D(h^3 + n) = t by isolating D. This problem involves algebraic concepts such as variable isolation and equation solving, ideal for students in Grades 9-12. The solution includes a detailed breakdown of each step.

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