Math Problem Statement

Solve each question in detail

Solve (y + zx)p - (x + yz)q = x^2 - y^2.

Solution

I'll go through the questions from the image you uploaded and provide detailed solutions for each. Let's start with Q1.

Q1: Solve (y+zx)p(x+yz)q=x2y2(y + zx)p - (x + yz)q = x^2 - y^2

  • Here, p=zxp = \frac{\partial z}{\partial x} and q=zyq = \frac{\partial z}{\partial y}.

    The equation becomes: (y+zx)zx(x+yz)zy=x2y2(y + zx) \frac{\partial z}{\partial x} - (x + yz) \frac{\partial z}{\partial y} = x^2 - y^2

    This is a linear first-order partial differential equation (PDE), and we can attempt to solve this using the method of characteristics.

The characteristic equations for this PDE can be written as: dxy+zx=dy(x+yz)=dzx2y2\frac{dx}{y + zx} = \frac{dy}{-(x + yz)} = \frac{dz}{x^2 - y^2}

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Math Problem Analysis

Mathematical Concepts

Partial Differential Equations
First-Order PDE
Method of Characteristics

Formulas

p = ∂z/∂x
q = ∂z/∂y

Theorems

Method of Characteristics for Solving First-Order PDEs

Suitable Grade Level

Undergraduate Level