We are given the expression:

\[
\frac{a^2 - 3c}{b}
\]

Substitute the values \(a = 2\), \(b = 3\), and \(c = -1\):

1. First, calculate \(a^2\):
   \[
   a^2 = 2^2 = 4
   \]

2. Now, calculate \(3c\):
   \[
   3c = 3 \times (-1) = -3
   \]

3. Substitute these values into the expression:
   \[
   \frac{a^2 - 3c}{b} = \frac{4 - (-3)}{3} = \frac{4 + 3}{3} = \frac{7}{3}
   \]

So, the final result is:

\[
\frac{7}{3}
\]

Would you like more details or have any questions?

Here are 5 related questions to explore:
1. What is the result if \(a = 4\), \(b = 2\), and \(c = -2\)?
2. How would the result change if we added a term \(d\) in the numerator?
3. Can you factor expressions similar to \(a^2 - 3c\) easily?
4. What happens when you apply the same operation to a quadratic expression?
5. How does simplifying fractions like \(\frac{7}{3}\) affect real-world applications?

**Tip:** Always simplify expressions step by step to avoid errors in algebraic manipulations.

Learn how to solve the algebraic expression a^2 - 3c divided by b, where a = 2, b = 3, and c = -1. This problem demonstrates key algebraic concepts such as substitution, exponents, and fractions, suitable for students in Grades 6-8.

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