To solve the expression \(36 \div (6 + 6) \times 5\), we will follow the order of operations, often remembered by the acronym PEMDAS (Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right)).

1. **Parentheses**: First, we calculate inside the parentheses:
   \[
   6 + 6 = 12
   \]
   So the expression now becomes:
   \[
   36 \div 12 \times 5
   \]

2. **Division and Multiplication**: Next, we perform the division and multiplication from left to right:
   \[
   36 \div 12 = 3
   \]
   \[
   3 \times 5 = 15
   \]

Thus, the final result is \( \boxed{15} \).

Would you like more details or have any questions?

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Here are 8 related questions to further your understanding:

1. What is the result of \(48 \div (8 + 4) \times 6\)?
2. How does the order of operations affect the result in \(24 \div (4 + 2) \times 3\)?
3. Can you solve \(72 \div (9 - 3) \times 4\)?
4. What is \(15 \times (8 - 2) \div 6\)?
5. If you change the expression to \(36 \div 6 + 6 \times 5\), what is the result?
6. How would the expression change if it was written as \(36 \div 6 \times (6 + 5)\)?
7. Solve \(54 \div (9 + 3) \times 4\).
8. What happens if you first multiply instead of dividing in the expression \(36 \div (6 + 6) \times 5\)?

**Tip:** Always handle operations inside parentheses first, and then proceed with division and multiplication from left to right.

Learn how to solve the expression 36 divided by the sum of 6 and 6, multiplied by 5, with a detailed step-by-step solution. This problem covers the order of operations (PEMDAS), arithmetic operations, and the use of parentheses. Suitable for students in Grades 6-8.

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