27 x (3 to the power of two then close bracket and to the power of 5

Let's break down the expression step by step:

1. You have the expression \( 27 \times (3^2)^5 \).
2. First, calculate \( 3^2 \), which is \( 9 \).
3. Then, raise \( 9 \) to the power of 5:  
   \( 9^5 = 9 \times 9 \times 9 \times 9 \times 9 = 59049 \).
4. Finally, multiply \( 27 \times 59049 \).

Let's calculate that final step.

\( 27 \times 59049 = 1,594,323 \).

So, the final answer is **1,594,323**.

Would you like more details or have any questions?

Here are 5 related questions you might explore:
1. What happens if the base is changed to 4 instead of 3?
2. How would you simplify expressions with multiple exponents, like \( (3^2)^3 \)?
3. How does the order of operations affect solving complex expressions?
4. What is the difference between powers and roots in an expression?
5. How do negative exponents affect calculations like this?

**Tip:** Always work from the inside out when solving complex expressions!

Learn how to solve the expression 27 x (3^2)^5 step by step. This problem covers key concepts in exponents and multiplication, using the laws of exponents and order of operations. Suitable for students in Grades 7-9.

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