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The equation provided is:

\[
x^2 = \frac{81}{64}
\]

To solve this using the square root property, we take the square root of both sides. The square root property states:

\[
x = \pm \sqrt{\frac{81}{64}}
\]

Now, we take the square roots of both the numerator and the denominator:

\[
x = \pm \frac{\sqrt{81}}{\sqrt{64}} = \pm \frac{9}{8}
\]

Thus, the solution to the equation is:

\[
x = \pm \frac{9}{8}
\]

### Final Answer:
\[
x = \frac{9}{8} \quad \text{or} \quad x = -\frac{9}{8}
\]

Would you like further details on the square root property or any related concepts?

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Here are 5 related questions you might find useful:
1. How do we simplify square roots of non-perfect squares?
2. Can the square root property be used for equations with negative terms?
3. What happens if the equation is \(x^2 = -\frac{81}{64}\)?
4. How does the square root property apply to complex numbers?
5. How can this method be extended to solve higher degree polynomials?

**Tip:** When solving quadratic equations using the square root property, remember to account for both the positive and negative roots, since squaring either value results in the same square.

Solve the equation using the square root property. x^2 = 81/64

Learn how to solve the quadratic equation x^2 = 81/64 using the square root property. This example demonstrates key algebraic concepts like square roots and the square root property, suitable for students in Grades 8-10.

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