To solve the equation $(x + 10)^2 = 2$, let's go through the steps:

1. Start by taking the square root of both sides to remove the square:

   $x + 10 = \pm \sqrt{2}$

   This gives us two possible equations:

   • $x + 10 = \sqrt{2}$
   • $x + 10 = -\sqrt{2}$

2. Solve each equation for $x$:

   For $x + 10 = \sqrt{2}$: $x = \sqrt{2} - 10$

   For $x + 10 = -\sqrt{2}$: $x = -\sqrt{2} - 10$

3. So, the solutions to the equation are: $x = \sqrt{2} - 10 \quad \text{and} \quad x = -\sqrt{2} - 10$

The correct answer is:

• A. The solution(s) is(are) $x = \sqrt{2} - 10, -\sqrt{2} - 10$

Let me know if you need further details or have any questions.

Here are some related questions you might find helpful:

1. How do you solve equations involving square roots?
2. What are the steps for isolating variables in quadratic equations?
3. How can you check if solutions are real or imaginary in quadratic equations?
4. How do different signs in an equation affect the solutions?
5. What is the role of the discriminant in quadratic equations?

Tip: Always check your solutions by substituting them back into the original equation to verify they satisfy it.