**If you subtract ½ from a number and multiply the result by ½, you get 1/8, what is the number?**

Let's solve the problem step by step.

1. **Define the unknown number:**  
   Let the unknown number be \( x \).

2. **Set up the equation based on the problem statement:**  
   According to the problem, if you subtract \( \frac{1}{2} \) from \( x \) and then multiply the result by \( \frac{1}{2} \), you get \( \frac{1}{8} \).  
   This can be expressed mathematically as:
   \[
   \frac{1}{2} \times (x - \frac{1}{2}) = \frac{1}{8}
   \]

3. **Simplify and solve the equation:**  
   To solve for \( x \), first distribute the \( \frac{1}{2} \) across the parentheses:
   \[
   \frac{1}{2}x - \frac{1}{4} = \frac{1}{8}
   \]

4. **Isolate \( x \):**  
   Add \( \frac{1}{4} \) to both sides to isolate the term involving \( x \):
   \[
   \frac{1}{2}x = \frac{1}{8} + \frac{1}{4}
   \]

5. **Find a common denominator to add the fractions:**  
   Convert \( \frac{1}{4} \) to have a denominator of 8:
   \[
   \frac{1}{4} = \frac{2}{8}
   \]
   Now add \( \frac{1}{8} + \frac{2}{8} \):
   \[
   \frac{1}{2}x = \frac{3}{8}
   \]

6. **Solve for \( x \):**  
   Multiply both sides of the equation by 2 to solve for \( x \):
   \[
   x = 2 \times \frac{3}{8} = \frac{6}{8} = \frac{3}{4}
   \]

Thus, the number is \( \frac{3}{4} \).

Would you like more details or have any questions?

Here are some related questions you might find interesting:

1. What is the process of solving linear equations with fractions?
2. How do you find the least common denominator when adding fractions?
3. How can you check if your solution to an equation is correct?
4. What are some common mistakes when solving equations with fractions?
5. Can this method be applied to equations involving decimals instead of fractions?

**Tip:** When solving equations with fractions, it’s often helpful to clear the fractions early by multiplying both sides by a common denominator.

Learn how to solve the equation where subtracting ½ from a number and multiplying by ½ equals 1/8. This problem covers basic arithmetic with fractions, suitable for students in Grades 5-7.

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