https://file.aiquickdraw.com/mathbot/file/17259251084880iss8ypr.jpg

The equation in the image is:

\[
h = D^2(B - 5g)
\]

We are tasked with solving for \( B \), taking care of letter capitalization.

### Step-by-step solution:

1. **Expand the equation:**
   \[
   h = D^2(B - 5g)
   \]
   Distribute \( D^2 \) on the right-hand side:
   \[
   h = D^2B - D^2(5g)
   \]
   Which simplifies to:
   \[
   h = D^2B - 5D^2g
   \]

2. **Isolate \( B \):**
   Add \( 5D^2g \) to both sides of the equation:
   \[
   h + 5D^2g = D^2B
   \]

3. **Solve for \( B \):**
   Finally, divide both sides by \( D^2 \) to isolate \( B \):
   \[
   B = \frac{h + 5D^2g}{D^2}
   \]

### Final Solution:
\[
B = \frac{h + 5D^2g}{D^2}
\]

Would you like a more detailed explanation or have any specific questions?

---

Here are some related questions to consider:

1. What happens if \( D = 0 \) in this equation?
2. How does the equation change if you square both sides at the beginning?
3. What if we are given specific values for \( h \), \( D \), and \( g \)? How would we calculate \( B \)?
4. How would this equation differ if we had a negative \( D^2 \)?
5. Can this equation be generalized for any power of \( D \) rather than just \( D^2 \)?

**Tip:** When solving for a variable, be mindful of any possible values of constants that might lead to undefined operations, such as division by zero.

Solve the following equation for B. Be sure to take into account whether a letter is capitalized or not. h = D^2(B - 5g)

Learn how to solve the algebraic equation h = D^2(B - 5g) for B. This step-by-step solution includes key algebraic concepts, focusing on solving for a variable in a linear equation.

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