It looks like there might be a typo in the equation due to the extra symbol after the \( g \). I'll assume the equation should be:

\[
78 = 8g + 14
\]

If this is correct, let's solve it.

### Steps to Solve \( 78 = 8g + 14 \):

1. **Subtract 14** from both sides to isolate the term with \( g \):
   \[
   78 - 14 = 8g
   \]
   Simplifying, we get:
   \[
   64 = 8g
   \]

2. **Divide both sides** by 8 to solve for \( g \):
   \[
   g = \frac{64}{8}
   \]
   Simplifying, we find:
   \[
   g = 8
   \]

So, the solution is \( g = 8 \).

Would you like more details, or do you have any questions?

Here are five related questions:
1. How would you solve \(50 = 5g + 10\)?
2. What is the next step if the equation was \(78 = 8g - 14\)?
3. Can you solve \(90 = 9g + 18\)?
4. What happens if the coefficient of \( g \) was negative?
5. How can you check if \( g = 8 \) is the correct solution?

**Tip:** Always perform inverse operations to isolate the variable when solving linear equations.

Learn how to solve the equation 78 = 8g + 14 with a detailed step-by-step solution. This problem covers key algebraic concepts, including linear equations and their solutions. Suitable for students in Grades 7-9.

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