Let's solve the equation step by step:

The given equation is:
\[
4x + 8 + 6x - 5 = 33
\]

1. **Combine like terms** on the left side:
   \[
   (4x + 6x) + (8 - 5) = 33
   \]
   This simplifies to:
   \[
   10x + 3 = 33
   \]

2. **Isolate the variable term** by subtracting 3 from both sides:
   \[
   10x = 33 - 3
   \]
   \[
   10x = 30
   \]

3. **Solve for \(x\)** by dividing both sides by 10:
   \[
   x = \frac{30}{10}
   \]
   \[
   x = 3
   \]

So, the solution is \( x = 3 \).

Would you like more details, or do you have any questions?

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Here are five related questions:

1. How would you solve the equation \(5x - 2 + 7x + 4 = 26\)?
2. What happens if you add a constant to both sides of an equation?
3. Can you solve \(3(2x + 1) = 18\)?
4. How do you solve an equation with variables on both sides, like \(2x + 5 = x + 9\)?
5. How can you verify the solution to an equation like the one we just solved?

**Tip:** Always combine like terms before trying to isolate the variable in an equation.

Learn how to solve the equation 4x + 8 + 6x - 5 = 33 with a detailed step-by-step solution. This problem covers key algebraic concepts, including combining like terms and isolating variables. Suitable for students in Grades 7-9.

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