if 33-a=a+27-5a what is the value of 33+3a

To solve for \( a \) in the equation \( 33 - a = a + 27 - 5a \), follow these steps:

### Step 1: Simplify the equation
Start by moving all terms involving \( a \) to one side of the equation and constants to the other side.

\[
33 - a = a + 27 - 5a
\]

Combine like terms on the right side:

\[
33 - a = -4a + 27
\]

### Step 2: Add \( 4a \) to both sides to eliminate the \( -4a \) term on the right:

\[
33 + 3a = 27
\]

### Step 3: Subtract 33 from both sides to isolate \( 3a \):

\[
3a = 27 - 33
\]

Simplify the right side:

\[
3a = -6
\]

### Step 4: Divide both sides by 3 to solve for \( a \):

\[
a = -2
\]

### Step 5: Find the value of \( 33 + 3a \)

Now that you know \( a = -2 \), substitute this value into \( 33 + 3a \):

\[
33 + 3(-2) = 33 - 6 = 27
\]

So, the value of \( 33 + 3a \) is **27**.

Would you like more details or have any questions?

Here are some related questions for further practice:

1. How would you solve the equation \( 33 - a = a + 27 - 5a \) step by step?
2. What happens if \( a = 0 \) in the original equation?
3. How would the equation change if the constant 33 were replaced with another number?
4. What if the original equation was \( 33 - 2a = a + 27 - 5a \)?
5. How can you verify the solution to the equation?
6. What would happen if the equation were multiplied by 2 on both sides?
7. Can you express \( a \) in terms of another variable?
8. How would the equation and its solution change if the minus signs were replaced with plus signs?

**Tip:** Always check your solution by substituting it back into the original equation to verify it satisfies the equation.

Learn how to solve the equation 33 - a = a + 27 - 5a with a detailed step-by-step solution. This problem covers key algebraic concepts, including equations and variable manipulation. Suitable for students in Grades 7-9.

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