It looks like you meant the equation as \( \frac{2x - 1}{4} = \frac{x - 7}{3} \). Here's how you solve it:

1. **Cross-multiply** to eliminate the fractions:

   \[
   3 \cdot (2x - 1) = 4 \cdot (x - 7)
   \]

   This simplifies to:

   \[
   6x - 3 = 4x - 28
   \]

2. **Move all terms involving \( x \)** to one side of the equation:
   - Subtract \( 4x \) from both sides:

   \[
   6x - 4x - 3 = -28
   \]

   Simplifying:

   \[
   2x - 3 = -28
   \]

3. **Isolate \( x \)**:
   - Add 3 to both sides:

   \[
   2x = -25
   \]

   - Divide both sides by 2:

   \[
   x = -\frac{25}{2}
   \]

So, the solution is \( x = -\frac{25}{2} \).

Would you like more details, or do you have any questions? 

Here are some related problems you might find interesting:
1. Solve \( \frac{3x - 2}{5} = \frac{2x + 1}{4} \).
2. Solve \( \frac{4x - 3}{6} = \frac{5x + 7}{8} \).
3. Solve \( \frac{5x + 4}{7} = \frac{3x - 9}{2} \).
4. Solve \( \frac{6x - 1}{8} = \frac{7x + 5}{9} \).
5. Solve \( \frac{7x + 2}{3} = \frac{4x - 8}{5} \).

**Tip:** When cross-multiplying, always ensure that the equation is in the form of one fraction equals another fraction before proceeding.

Learn how to solve the equation (2x - 1) / 4 = (x - 7) / 3 with a detailed step-by-step solution. This problem covers key algebraic concepts, including solving equations with fractions and cross-multiplication. Suitable for students in Grades 7-9.

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