To solve the equation \(22 = -3 + (6 - 1)d\), follow these steps:

1. Simplify the expression inside the parentheses:
   \[
   6 - 1 = 5
   \]
   So, the equation becomes:
   \[
   22 = -3 + 5d
   \]

2. Add 3 to both sides of the equation to isolate the term with \(d\):
   \[
   22 + 3 = 5d
   \]
   \[
   25 = 5d
   \]

3. Divide both sides by 5 to solve for \(d\):
   \[
   d = \frac{25}{5} = 5
   \]

So, the solution is \(d = 5\).

Would you like more details or have any questions about this solution?

Here are some related questions:
1. How do you solve equations with variables on both sides?
2. What is the difference between solving linear equations and quadratic equations?
3. How do you check if your solution to an equation is correct?
4. What happens if an equation has no solution or infinite solutions?
5. Can you solve an equation where the variable is in the denominator?

**Tip:** Always double-check your calculations, especially when simplifying expressions, to avoid small mistakes.

Learn how to solve the equation 22 = -3 + (6 - 1)d with a detailed step-by-step solution. This problem involves basic algebraic equations and is suitable for students in Grades 7-9.

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