To solve the equation \( \frac{15}{45} = \frac{x}{48} \), follow these steps:

1. Simplify the left side of the equation:
   \[
   \frac{15}{45} = \frac{1}{3}
   \]
   So the equation simplifies to:
   \[
   \frac{1}{3} = \frac{x}{48}
   \]

2. Now, cross-multiply to solve for \( x \):
   \[
   1 \times 48 = 3 \times x
   \]
   \[
   48 = 3x
   \]

3. Divide both sides by 3 to isolate \( x \):
   \[
   x = \frac{48}{3} = 16
   \]

So, \( x = 16 \).

Would you like more details on any step, or do you have any questions?

Here are 5 related questions to explore:

1. How do you simplify fractions like \( \frac{15}{45} \)?
2. What is cross-multiplication and when is it used?
3. Can you solve for \( x \) in \( \frac{7}{21} = \frac{x}{9} \)?
4. What happens if the equation has negative numbers?
5. How do you solve equations where both fractions are complex?

**Tip:** Always simplify fractions first to make solving equations easier!

Learn how to solve the equation 15/45 = x/48 with a detailed step-by-step solution. This problem involves fractions and cross-multiplication methods. Suitable for students in Grades 6-8.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation