It looks like you're trying to express an equation using algebra. Let me rewrite it properly and explain the solution.

Your equation seems to be:

\[
10x + 3x + 2 = 13x + 2
\]

Now let's simplify and solve:

### Step 1: Combine like terms on the left-hand side.
On the left-hand side of the equation, combine the terms involving \( x \):

\[
10x + 3x + 2 = 13x + 2
\]
\[
13x + 2 = 13x + 2
\]

### Step 2: Analyze the equation.
Notice that both sides of the equation are identical:

\[
13x + 2 = 13x + 2
\]

This means the equation is **always true** for any value of \( x \). Therefore, there is no specific solution for \( x \); the equation holds for all values of \( x \).

### Conclusion
The perimeter of the triangle is \( 13x + 2 \). Since the equation is true for all \( x \), the perimeter will depend on the value of \( x \), but the relationship will always be valid.

Let me know if you have any further questions! Here are some related questions for you to consider:

1. What happens if the equation was not identical on both sides?
2. Could you solve for a specific value of \( x \) if one of the triangles had a different perimeter?
3. How does changing the coefficient of \( x \) affect the perimeter of the triangles?
4. What if there was an additional constant added to one side of the equation?
5. Can you write another equation with different side lengths but the same perimeter?

**Tip:** Identical equations, like the one above, show that the relationship holds universally for any value of the variable.

Learn how to solve the equation 10x + 3x + 2 = 13x + 2 with a detailed step-by-step solution. This problem covers key algebraic concepts, including equations and expressions. Suitable for students in Grades 7-9.

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