Math Problem Statement

Victoria holds a fishing pole with fishing line extended according to the picture. How far is the fish from her hook? (Solve for x)

Solution

We can solve this problem using the Pythagorean Theorem, since the scenario forms a right triangle.

From the image:

  • The hypotenuse (the fishing line) is 25.5 feet.
  • The vertical leg (the difference between the total height of Victoria and the height of the water level) is 73=47 - 3 = 4 feet.
  • The horizontal leg (the distance from Victoria to the fish along the water, which is the value of xx) is what we're solving for.

According to the Pythagorean Theorem: a2+b2=c2a^2 + b^2 = c^2 Where:

  • aa is the vertical leg (4 feet),
  • bb is the horizontal leg (which is xx, the distance we need to find),
  • cc is the hypotenuse (25.5 feet).

Now, we can substitute the known values: 42+x2=25.524^2 + x^2 = 25.5^2 16+x2=650.2516 + x^2 = 650.25 Subtract 16 from both sides: x2=650.2516x^2 = 650.25 - 16 x2=634.25x^2 = 634.25 Now, take the square root of both sides to find xx: x=634.2525.19feetx = \sqrt{634.25} \approx 25.19 \, \text{feet}

Thus, the distance from Victoria to the fish, xx, is approximately 25.19 feet.

Would you like more details or have any questions?

Here are some related questions:

  1. How does the Pythagorean Theorem apply to real-world scenarios like this?
  2. What is the significance of each leg in the right triangle?
  3. How can the accuracy of the measurements affect the result?
  4. What if the fishing line was longer—how would that change the distance?
  5. Can you generalize the formula to solve similar problems with different dimensions?

Tip: Always ensure you're identifying the correct sides of the triangle before applying the Pythagorean Theorem.

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Math Problem Analysis

Mathematical Concepts

Geometry
Right Triangles
Pythagorean Theorem

Formulas

a^2 + b^2 = c^2 (Pythagorean Theorem)

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 8-10