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The inequality you provided is:

\[
-25 > -2x - 5 > -29
\]

To solve this compound inequality, we will break it into two parts and solve for \(x\) step by step.

### Step 1: Solve the left inequality: 
\[
-25 > -2x - 5
\]
1. Add 5 to both sides:
   \[
   -25 + 5 > -2x
   \]
   \[
   -20 > -2x
   \]
2. Divide both sides by \(-2\) (and reverse the inequality sign since we're dividing by a negative number):
   \[
   \frac{-20}{-2} < \frac{-2x}{-2}
   \]
   \[
   10 < x
   \]
   This simplifies to:
   \[
   x > 10
   \]

### Step 2: Solve the right inequality: 
\[
-2x - 5 > -29
\]
1. Add 5 to both sides:
   \[
   -2x - 5 + 5 > -29 + 5
   \]
   \[
   -2x > -24
   \]
2. Divide both sides by \(-2\) (again, reversing the inequality sign):
   \[
   \frac{-2x}{-2} < \frac{-24}{-2}
   \]
   \[
   x < 12
   \]

### Step 3: Combine the results

From both steps, we have:
\[
10 < x < 12
\]

Thus, the solution to the inequality is:
\[
x \in (10, 12)
\]

This means \(x\) must be greater than 10 and less than 12.

Would you like more details or further clarification on any step?

### Related Questions:
1. What would happen if the inequality sign was non-strict (e.g., \(\geq\) or \(\leq\))?
2. How do you graph compound inequalities on a number line?
3. What changes when solving inequalities if you multiply or divide by a negative number?
4. How can you verify your solution to inequalities?
5. What are some real-life applications of solving compound inequalities?

**Tip:** Always remember to reverse the inequality sign when multiplying or dividing by a negative number in an inequality.

Learn how to solve the compound inequality -25 > -2x - 5 > -29 step by step. This problem involves key algebraic concepts, including solving inequalities and handling negative coefficients. Suitable for students in Grades 7-9.

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