To solve the inequality \(0 \leq p + 20 < 3\), we can split it into two parts:

### Step 1: Solve \(0 \leq p + 20\)
1. Subtract 20 from both sides:
   \[
   0 - 20 \leq p + 20 - 20
   \]
   \[
   -20 \leq p
   \]
   or
   \[
   p \geq -20
   \]

### Step 2: Solve \(p + 20 < 3\)
1. Subtract 20 from both sides:
   \[
   p + 20 - 20 < 3 - 20
   \]
   \[
   p < -17
   \]

### Combine the Results
The solution to the compound inequality \(0 \leq p + 20 < 3\) is:
\[
-20 \leq p < -17
\]
or
\[
p \in [-20, -17)
\]

Would you like more details or have any questions?

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Here are five related questions to practice further:

1. Solve \(0 \leq p + 15 < 4\).
2. Solve \(-10 \leq p - 5 < 2\).
3. Solve \(3 \leq 2p + 10 < 9\).
4. Determine the solution for \(5 \leq 3x - 1 < 8\).
5. Solve \(1 \leq 4y + 7 < 15\).

**Tip:** When solving compound inequalities, break them into two parts and solve each inequality separately before combining the results.

Learn how to solve the compound inequality 0 ≤ p + 20 < 3 with a detailed step-by-step solution. This problem involves solving inequalities, including subtracting constants and combining results. Suitable for students in Grades 7-9.

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