To find the values of $x$ and $y$ in this triangle, we can use the properties of parallel lines and angles.

1. Identify the Parallel Lines and Transversal:

   • The two lines $AB$ and $DC$ appear to be marked as parallel (indicated by the arrow notation on both sides).
   • $AD$ acts as a transversal between these parallel lines.

2. Using Corresponding Angles:

   • Since $AB \parallel DC$ and $AD$ is a transversal, angle $BAD$ (which is $x$) is equal to angle $EDC$, due to the property of corresponding angles. Therefore, we have: $x = 63^\circ$

3. Using the Angle Sum of a Triangle:

   • Now, look at triangle $ABD$. The sum of angles in a triangle is $180^\circ$.
   • We know: $\angle ADB = 90^\circ \quad \text{(since it's marked as a right angle)}$
   • Therefore, in $\triangle ABD$: $\angle BAD + \angle ABD + \angle ADB = 180^\circ$ $x + x + 90^\circ = 180^\circ$ $2x = 90^\circ$ $x = 45^\circ$

   After revisiting, the answer