3|x+y|to the power of 2-(xy)to the power of 2 if x=3 and 7=-5

It seems like there might be a typo in your input. It looks like you intended to provide specific values for \(x\) and \(y\), but there's an error in the statement. I assume you meant to assign values to \(x\) and \(y\). Let's assume you meant \(x = 3\) and \(y = -5\).

Given the expression:

\[
(3|x + y|)^2 - (xy)^2
\]

We substitute \(x = 3\) and \(y = -5\) into the expression.

### Step 1: Calculate \(x + y\)
\[
x + y = 3 + (-5) = -2
\]

### Step 2: Calculate the absolute value of \(x + y\)
\[
|x + y| = |-2| = 2
\]

### Step 3: Substitute into the first term
\[
3|x + y| = 3 \times 2 = 6
\]
\[
(3|x + y|)^2 = 6^2 = 36
\]

### Step 4: Calculate the product \(xy\)
\[
xy = 3 \times (-5) = -15
\]
\[
(xy)^2 = (-15)^2 = 225
\]

### Step 5: Substitute and combine
The expression becomes:

\[
36 - 225 = -189
\]

So, the final result is:

\[
-189
\]

Would you like more details or explanations on any of these steps?

### Relative Questions:

1. What is the effect of absolute value in algebraic expressions?
2. How do you handle exponents when dealing with negative numbers?
3. What are some real-world applications of algebraic expressions?
4. How do you simplify expressions involving both absolute values and powers?
5. What are the differences between evaluating expressions with positive and negative values?

### Tip:
Always double-check the signs when substituting values into an expression, especially when dealing with absolute values and powers. This helps avoid common errors.

Learn how to solve the algebraic expression 3|x+y|^2 - (xy)^2 with detailed step-by-step instructions. This problem involves evaluating absolute values, calculating exponents, and substituting values into algebraic expressions. Suitable for Grades 7-9 students.

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