Solve for u.
5
6
u+2–u=
1
6
u
u=
without explaining

The equation you provided seems unclear, but based on an interpretation of it as:

\[
\frac{5}{6}(u + 2 - u) = \frac{1}{6}u
\]

Here’s the solution:

\[
\frac{5}{6}(2) = \frac{1}{6}u
\]

\[
\frac{10}{6} = \frac{1}{6}u
\]

Multiplying both sides by 6:

\[
10 = u
\]

So, \( u = 10 \).

Would you like to review the details or ask any questions?

Here are 5 related questions:
1. How do we handle equations with fractions?
2. How do we solve for a variable when it appears on both sides of the equation?
3. What happens if the variable appears in a more complex form?
4. How do you verify solutions in an equation?
5. What steps are involved when simplifying terms?

**Tip:** Always multiply by the least common denominator to eliminate fractions early on in an equation.

Learn how to solve the algebraic equation 5/6(u+2–u) = 1/6u by isolating the variable u and using equation balancing with fractions. This step-by-step guide covers key concepts in algebra, suitable for students in Grades 7-9.

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