To solve \(\left(\frac{-3}{-4}\right)^2\), follow these steps:

1. **Simplify the fraction**: 
   \[
   \frac{-3}{-4} = \frac{3}{4}
   \]
   because the negatives cancel out.

2. **Square the simplified fraction**:
   \[
   \left(\frac{3}{4}\right)^2 = \frac{3^2}{4^2} = \frac{9}{16}
   \]

So, \(\left(\frac{-3}{-4}\right)^2 = \frac{9}{16}\).

Would you like a more detailed explanation or have any other questions?

Here are 5 related questions:

1. What is \(\left(\frac{5}{-7}\right)^2\)?
2. How do you simplify the expression \(\left(\frac{-2}{3}\right)^3\)?
3. What is \(\left(\frac{-6}{-8}\right)^2\)?
4. How do you calculate \(\left(\frac{-4}{5}\right)^2\)?
5. What is the square of \(\left(\frac{7}{9}\right)\)?

**Tip:** When squaring a fraction, square both the numerator and the denominator separately.

Learn how to solve the expression (-3/-4)^2 with a step-by-step explanation. This problem involves simplifying fractional exponents and squaring fractions, suitable for students in Grades 7-9.

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