The problem asks to determine which point among the given options satisfies the inequality $x > 3y - 2$.

The options provided are:

• (2, 3)
• (5, 0)
• (-2, 0)
• (-2, 5)

We will check each point to see if it satisfies the inequality.

1. For (2, 3): $x = 2, \quad y = 3$ Check if: $2 > 3(3) - 2$ $2 > 9 - 2$ $2 > 7 \quad \text{(False)}$ So, (2, 3) is not a solution.

2. For (5, 0): $x = 5, \quad y = 0$ Check if: $5 > 3(0) - 2$ $5 > 0 - 2$ $5 > -2 \quad \text{(True)}$ So, (5, 0) is a solution.

3. For (-2, 0): $x = -2, \quad y = 0$ Check if: $-2 > 3(0) - 2$ $-2 > 0 - 2$ $-2 > -2 \quad \text{(False)}$ So, (-2, 0) is not a solution.

4. For (-2, 5): $x = -2, \quad y = 5$ Check if: $-2 > 3(5) - 2$ $-2 > 15 - 2$ $-2 > 13 \quad \text{(False)}$ So, (-2, 5) is not a solution.

Conclusion:

The correct solution is (5, 0).

Would you like a more detailed explanation or have any questions?

Here are 5 related questions:

1. How do you solve inequalities involving two variables?
2. What is the geometric representation of inequalities like $x > 3y - 2$?
3. Can a point satisfy more than one inequality?
4. How do systems of inequalities work?
5. What happens when you reverse the inequality sign?

Tip: When solving inequalities, always test each point by substituting the coordinates into the inequality to check if it holds true.