The given equation is $3x + y = -2$.

To find the slope and the y-intercept, rewrite the equation in the slope-intercept form $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept.

Steps:

1. Start with the given equation: $3x + y = -2$

2. Isolate $y$ on one side: $y = -3x - 2$

Slope and Y-Intercept:

• Slope ($m$): $-3$
• Y-Intercept ($b$): $-2$

Thus, the slope is $-3$, and the y-intercept is the point $(0, -2)$.

Would you like further details or assistance with this? Here are some related questions:

1. How can we graph the line using the slope and y-intercept?
2. What is the equation of a line parallel to this one?
3. How do we find the x-intercept of the line?
4. How do we calculate the distance of this line from a given point?
5. What is the equation of a perpendicular line passing through a specific point?

Tip: Always double-check the slope-intercept form for clarity when determining slope and y-intercept.