slope of the line through the points (3,-7) and (-8,-9)

The slope of a line through two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by the formula:

\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]

For the points \((3, -7)\) and \((-8, -9)\):

\[
m = \frac{-9 - (-7)}{-8 - 3} = \frac{-9 + 7}{-8 - 3} = \frac{-2}{-11} = \frac{2}{11}
\]

Thus, the slope of the line is \(\frac{2}{11}\).

Would you like further explanation or have any questions about this?

Here are five related questions for further exploration:
1. What is the equation of the line passing through these two points?
2. How do you find the y-intercept of a line given its slope and a point?
3. What is the slope of a line parallel to this one?
4. What is the slope of a line perpendicular to this one?
5. How does the slope relate to the steepness of a line?

**Tip**: A positive slope indicates that the line rises as you move from left to right, while a negative slope indicates it falls.

Learn how to calculate the slope of the line passing through the points (3, -7) and (-8, -9) using the slope formula. This algebra problem demonstrates key concepts in coordinate geometry, suitable for students in Grades 8-10.

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