The expression $\sqrt{8}$ simplifies as follows:

1. First, break down $8$ into factors to find any perfect squares: $8 = 4 \times 2$

2. Rewrite the square root as: $\sqrt{8} = \sqrt{4 \times 2} = \sqrt{4} \times \sqrt{2}$

3. Since $\sqrt{4} = 2$, this becomes: $\sqrt{8} = 2\sqrt{2}$

Therefore: $\sqrt{8} = 2\sqrt{2}$

Would you like further details, or do you have any questions?

Here are some related questions:

1. How do we simplify other square roots, like $\sqrt{18}$?
2. What is the decimal approximation of $\sqrt{2}$?
3. How would we handle $\sqrt{8x}$ in algebraic expressions?
4. How can we rationalize expressions involving square roots?
5. How do we multiply square roots, such as $\sqrt{8} \times \sqrt{2}$?

Tip: Breaking down numbers under square roots into their prime factors often reveals perfect squares, making it easier to simplify.