Math Problem Statement

Divide. Express your answer in lowest terms. StartFraction 3 k squared minus 2 k minus 1 Over 3 k squared plus 10 k plus 7 EndFraction 3k2−2k−1 3k2+10k+7 divided by ÷StartFraction 9 k squared minus 1 Over 3 k squared plus 4 k minus 7 EndFraction 9k2−1 3k2+4k−7

Solution

Let's break down the problem step-by-step.

The problem is:

3k22k13k2+10k+7÷9k213k2+4k7\frac{3k^2 - 2k - 1}{3k^2 + 10k + 7} \div \frac{9k^2 - 1}{3k^2 + 4k - 7}

Step 1: Changing division into multiplication

Dividing by a fraction is the same as multiplying by its reciprocal. So, we first rewrite the expression as:

3k22k13k2+10k+7×3k2+4k79k21\frac{3k^2 - 2k - 1}{3k^2 + 10k + 7} \times \frac{3k^2 + 4k - 7}{9k^2 - 1}

Step 2: Factorization of the quadratics

Now, let's factor each of the quadratics:

  1. Factor 3k22k13k^2 - 2k - 1: We need to find two numbers that multiply to 3×(1)=33 \times (-1) = -3 and add to 2-2. These numbers are 3-3 and 11.

    Therefore: 3k22k1=(3k+1)(k1)3k^2 - 2k - 1 = (3k + 1)(k - 1)

  2. Factor 3k2+10k+73k^2 + 10k + 7: We need two numbers that multiply to 3×7=213 \times 7 = 21 and add to 1010. These numbers are 33 and 77.

    Therefore: 3k2+10k+7=(3k+7)(k+1)3k^2 + 10k + 7 = (3k + 7)(k + 1)

  3. Factor 9k219k^2 - 1 (difference of squares): 9k21=(3k1)(3k+1)9k^2 - 1 = (3k - 1)(3k + 1)

  4. Factor 3k2+4k73k^2 + 4k - 7: We need two numbers that multiply to 3×(7)=213 \times (-7) = -21 and add to 44. These numbers are 77 and 3-3.

    Therefore: 3k2+4k7=(3k7)(k+1)3k^2 + 4k - 7 = (3k - 7)(k + 1)

Step 3: Substitute the factors into the expression

Now, we can substitute the factors we found into the expression:

(3k+1)(k1)(3k+7)(k+1)×(3k7)(k+1)(3k1)(3k+1)\frac{(3k + 1)(k - 1)}{(3k + 7)(k + 1)} \times \frac{(3k - 7)(k + 1)}{(3k - 1)(3k + 1)}

Step 4: Simplify the expression

We can cancel out the common factors in the numerator and denominator:

  • (3k+1)(3k + 1) appears in both the numerator and denominator, so it cancels.
  • (k+1)(k + 1) appears in both the numerator and denominator, so it cancels.

The remaining expression is:

(k1)(3k7)(3k+7)(3k1)\frac{(k - 1)(3k - 7)}{(3k + 7)(3k - 1)}

Step 5: Final Answer

The simplified expression in lowest terms is:

(k1)(3k7)(3k+7)(3k1)\frac{(k - 1)(3k - 7)}{(3k + 7)(3k - 1)}

Would you like more explanation or further steps on how to work with rational expressions?

Here are some related questions you can explore:

  1. How do you factor trinomials when the leading coefficient is not 1?
  2. What does it mean for rational expressions to be in lowest terms?
  3. How do you solve rational equations involving polynomials?
  4. How can you perform polynomial long division to simplify expressions?
  5. What are the common mistakes when factoring quadratics?

Tip: Always check for common factors across the numerator and denominator in rational expressions before simplifying!

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Math Problem Analysis

Mathematical Concepts

Algebra
Rational Expressions
Factoring Quadratics
Simplifying Fractions

Formulas

Division of fractions
Difference of squares
Factoring trinomials

Theorems

Factorization of quadratics
Multiplying by the reciprocal

Suitable Grade Level

Grades 9-11