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The equation you've provided is:

\[
y = \frac{x^2 + 3x}{x}
\]

To simplify this expression, observe that the numerator can be factored and simplified as follows:

\[
y = \frac{x(x + 3)}{x}
\]

As long as \( x \neq 0 \), the \( x \) terms in the numerator and denominator cancel each other out:

\[
y = x + 3
\]

Therefore, the simplified form of the equation is:

\[
y = x + 3
\]

Would you like any more details on this problem, or do you have additional questions?

Here are five related questions for deeper understanding:

1. What is the domain of the function \( y = \frac{x^2 + 3x}{x} \)?
2. How would you graph the function \( y = x + 3 \)?
3. What are the intercepts of the equation \( y = x + 3 \)?
4. How would you find the derivative of \( y = x + 3 \)?
5. What happens to the function \( y = \frac{x^2 + 3x}{x} \) when \( x = 0 \)?

**Tip:** Always check if you can simplify an expression by factoring common terms; this often makes it easier to analyze or solve the problem!

Learn how to simplify the rational expression y = (x^2 + 3x) / x. This algebra problem demonstrates factoring and canceling common terms, suitable for students in Grades 8-10.

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