simplify leaving your answer in the form a+b root c root 5 all over 2root2-root5 + root 2 all over 2root2+root 5

To simplify the expression you provided:

\[
\frac{a + b \sqrt{c}}{2\sqrt{2} - \sqrt{5}} + \frac{\sqrt{2}}{2\sqrt{2} + \sqrt{5}}
\]

We will start by simplifying both terms. We’ll tackle them one by one, using rationalization for the denominators.

### Step 1: Rationalize the first term
The first term is:

\[
\frac{a + b \sqrt{c}}{2\sqrt{2} - \sqrt{5}}
\]

To rationalize the denominator, we multiply both the numerator and denominator by the conjugate of the denominator, which is \(2\sqrt{2} + \sqrt{5}\):

\[
\frac{a + b \sqrt{c}}{2\sqrt{2} - \sqrt{5}} \times \frac{2\sqrt{2} + \sqrt{5}}{2\sqrt{2} + \sqrt{5}} = \frac{(a + b \sqrt{c})(2\sqrt{2} + \sqrt{5})}{(2\sqrt{2})^2 - (\sqrt{5})^2}
\]

### Step 2: Simplify the denominator
Now, let's simplify the denominator:

\[
(2\sqrt{2})^2 = 4 \times 2 = 8
\]
\[
(\sqrt{5})^2 = 5
\]
So, the denominator becomes:

\[
8 - 5 = 3
\]

### Step 3: Expand the numerator
Next, expand the numerator:

\[
(a + b \sqrt{c})(2\sqrt{2} + \sqrt{5}) = a(2\sqrt{2}) + a(\sqrt{5}) + b \sqrt{c} (2\sqrt{2}) + b \sqrt{c} (\sqrt{5})
\]

\[
= 2a\sqrt{2} + a\sqrt{5} + 2b \sqrt{2c} + b \sqrt{5c}
\]

Thus, the first term simplifies to:

\[
\frac{2a\sqrt{2} + a\sqrt{5} + 2b \sqrt{2c} + b \sqrt{5c}}{3}
\]

### Step 4: Rationalize the second term
The second term is:

\[
\frac{\sqrt{2}}{2\sqrt{2} + \sqrt{5}}
\]

We rationalize by multiplying by the conjugate \(2\sqrt{2} - \sqrt{5}\):

\[
\frac{\sqrt{2}}{2\sqrt{2} + \sqrt{5}} \times \frac{2\sqrt{2} - \sqrt{5}}{2\sqrt{2} - \sqrt{5}} = \frac{\sqrt{2}(2\sqrt{2} - \sqrt{5})}{(2\sqrt{2})^2 - (\sqrt{5})^2}
\]

The denominator simplifies as before to:

\[
8 - 5 = 3
\]

Now expand the numerator:

\[
\sqrt{2}(2\sqrt{2} - \sqrt{5}) = \sqrt{2}(2\sqrt{2}) - \sqrt{2}(\sqrt{5}) = 2 \times 2 - \sqrt{10} = 4 - \sqrt{10}
\]

Thus, the second term becomes:

\[
\frac{4 - \sqrt{10}}{3}
\]

### Step 5: Combine the terms
Now, we can combine both terms, remembering that both denominators are the same:

\[
\frac{2a\sqrt{2} + a\sqrt{5} + 2b \sqrt{2c} + b \sqrt{5c}}{3} + \frac{4 - \sqrt{10}}{3}
\]

Combine the numerators:

\[
\frac{(2a\sqrt{2} + a\sqrt{5} + 2b \sqrt{2c} + b \sqrt{5c}) + (4 - \sqrt{10})}{3}
\]

### Final Expression:
Thus, the simplified expression is:

\[
\frac{2a\sqrt{2} + a\sqrt{5} + 2b \sqrt{2c} + b \sqrt{5c} + 4 - \sqrt{10}}{3}
\]

---

Would you like me to provide further details or clarifications on any of these steps? Here are a few related questions you might find interesting:

1. How do you rationalize a denominator in general?
2. What happens when we multiply binomials with square roots in them?
3. How do you combine like terms when dealing with square roots?
4. What are some strategies for simplifying expressions with mixed square roots and constants?
5. Can you explain how to handle expressions with square roots in both the numerator and denominator?

**Tip:** Always check if the denominator is rationalized before simplifying further to avoid complicating the expression!

Learn how to simplify complex expressions involving square roots by rationalizing the denominators and expanding binomials. The step-by-step guide shows how to handle mixed square roots in both the numerator and denominator, suitable for high school algebra students.

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