Let's break down the expression \(\frac{6 + \sqrt{9}}{2 \times 3}\).

1. First, simplify \(\sqrt{9}\):
   \[
   \sqrt{9} = 3
   \]

2. Replace \(\sqrt{9}\) in the original expression:
   \[
   \frac{6 + 3}{2 \times 3}
   \]

3. Simplify the numerator \(6 + 3\):
   \[
   6 + 3 = 9
   \]

4. Simplify the denominator \(2 \times 3\):
   \[
   2 \times 3 = 6
   \]

5. Now, the expression becomes:
   \[
   \frac{9}{6}
   \]

6. Simplify \(\frac{9}{6}\):
   \[
   \frac{9}{6} = \frac{3}{2}
   \]

Thus, the simplified result is \(\frac{3}{2}\) or 1.5.

Would you like further details or explanations on any step?

Here are 5 related questions:
1. How do you simplify square roots like \(\sqrt{25}\)?
2. What is the difference between rational and irrational numbers?
3. How do you simplify complex fractions?
4. How do you add and subtract radical expressions?
5. How can you apply the distributive property in more complex problems?

**Tip:** When simplifying, always handle square roots and parentheses first to avoid mistakes.

Learn how to simplify the expression (6 + sqrt(9))/(2(3)) using square roots and basic algebraic operations. This problem explains the process of simplifying fractions and handling square roots, suitable for students in Grades 6-8.

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