Math Problem Statement

1 + 5i + 2i^2 - 23i^3

Solution

The given expression in the image is:

1+5i+2i223i31 + 5i + 2i^2 - 23i^3

Step-by-Step Solution:

  1. Simplify Powers of ii:

    • We know that ii is the imaginary unit where i2=1i^2 = -1.
    • i3=i2i=1i=ii^3 = i^2 \cdot i = -1 \cdot i = -i.
  2. Substitute these values:

    • i2=1i^2 = -1,
    • i3=ii^3 = -i.

Thus, the expression becomes: 1+5i+2(1)23(i)1 + 5i + 2(-1) - 23(-i)

This simplifies to: 1+5i2+23i1 + 5i - 2 + 23i

  1. Combine real and imaginary parts:
    • Real part: 12=11 - 2 = -1,
    • Imaginary part: 5i+23i=28i5i + 23i = 28i.

Therefore, the simplified expression is: 1+28i-1 + 28i

This is the final form of the expression in standard form a+bia + bi, where a=1a = -1 and b=28b = 28.


Would you like more details on how powers of ii work, or any other part of the process?

Here are 5 related questions:

  1. What are the higher powers of ii beyond i3i^3?
  2. How do we graph complex numbers like 1+28i-1 + 28i on the complex plane?
  3. What are some applications of imaginary numbers in real-life scenarios?
  4. How would you add or subtract two complex numbers?
  5. Can you multiply or divide two complex numbers, and what does the result represent?

Tip: Always simplify powers of ii in steps when working with complex numbers to avoid errors.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Imaginary Unit
Algebra

Formulas

i^2 = -1
i^3 = -i

Theorems

Powers of i Theorem

Suitable Grade Level

Grades 10-12