m -  (p^2  - (p  + p)) when m  = 6  and p = 2

Let's solve the expression \( m - (p^2 - (p + p)) \) given \( m = 6 \) and \( p = 2 \).

### Step 1: Substitute the values of \( m \) and \( p \) into the expression.

\[
6 - \left(2^2 - (2 + 2)\right)
\]

### Step 2: Calculate \( p^2 \).

\[
2^2 = 4
\]

### Step 3: Calculate \( p + p \).

\[
2 + 2 = 4
\]

### Step 4: Substitute these values back into the expression.

\[
6 - \left(4 - 4\right)
\]

### Step 5: Simplify the expression inside the parentheses.

\[
4 - 4 = 0
\]

### Step 6: Subtract the result from \( m \).

\[
6 - 0 = 6
\]

So, the final answer is \( \boxed{6} \).

Would you like any further details or have any questions? 

Here are five related questions to explore:
1. What happens if \( p = 3 \)? How does the expression change?
2. How would the expression change if \( m \) was a different number?
3. What is the general form of this expression in terms of \( m \) and \( p \)?
4. Can you create a different expression using \( m \) and \( p \) that equals zero?
5. How does the expression behave as \( p \) increases or decreases?

**Tip:** When simplifying expressions, always work from the innermost parentheses outwards.

Explore the step-by-step process to simplify the algebraic expression m - (p^2 - (p + p)) where m = 6 and p = 2. This problem is ideal for students in Grades 6-8, focusing on algebraic substitution and the order of operations.

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