Math Problem Statement

The expression \( \frac{(\sqrt{x^3yz^{-3}})(\sqrt{y^5x^{-1}z})}{x^{-2}y^{-1}z^{- rac{1}{2}}} \) is equal to?

Solution

The expression you are asked to simplify is:

(x3yz3)(y5x1z)x2y1z12\frac{\left(\sqrt{x^3yz^{-3}}\right)\left(\sqrt{y^5x^{-1}z}\right)}{x^{-2}y^{-1}z^{-\frac{1}{2}}}

Step-by-Step Simplification:

  1. Simplify the square roots:

    • For x3yz3\sqrt{x^3yz^{-3}}, we take the square root of each term: x3yz3=x3/2y1/2z3/2\sqrt{x^3yz^{-3}} = x^{3/2}y^{1/2}z^{-3/2}
    • For y5x1z\sqrt{y^5x^{-1}z}, we also take the square root of each term: y5x1z=x1/2y5/2z1/2\sqrt{y^5x^{-1}z} = x^{-1/2}y^{5/2}z^{1/2}
  2. Multiply the two expressions under the square roots: (x3/2y1/2z3/2)(x1/2y5/2z1/2)\left(x^{3/2}y^{1/2}z^{-3/2}\right) \cdot \left(x^{-1/2}y^{5/2}z^{1/2}\right) Multiply the terms with the same base:

    • For xx: x3/2x1/2=x(3/21/2)=x1x^{3/2} \cdot x^{-1/2} = x^{(3/2 - 1/2)} = x^1
    • For yy: y1/2y5/2=y(1/2+5/2)=y3y^{1/2} \cdot y^{5/2} = y^{(1/2 + 5/2)} = y^3
    • For zz: z3/2z1/2=z(3/2+1/2)=z1z^{-3/2} \cdot z^{1/2} = z^{(-3/2 + 1/2)} = z^{-1} So the product is: xy3z1x \cdot y^3 \cdot z^{-1}
  3. Divide by the denominator x2y1z1/2x^{-2}y^{-1}z^{-1/2}: Now divide the expression xy3z1x \cdot y^3 \cdot z^{-1} by x2y1z1/2x^{-2}y^{-1}z^{-1/2}: xy3z1x2y1z1/2=x(1(2))y(3(1))z(1(1/2))\frac{x \cdot y^3 \cdot z^{-1}}{x^{-2}y^{-1}z^{-1/2}} = x^{(1 - (-2))} \cdot y^{(3 - (-1))} \cdot z^{(-1 - (-1/2))} Simplify each exponent:

    • For xx: x(1+2)=x3x^{(1 + 2)} = x^3
    • For yy: y(3+1)=y4y^{(3 + 1)} = y^4
    • For zz: z(1+1/2)=z1/2z^{(-1 + 1/2)} = z^{-1/2} So the simplified expression is: x3y4z1/2x^3 \cdot y^4 \cdot z^{-1/2}
  4. Final Result: The expression simplifies to: (y4x3z1/2)1/2=y2x3/2z1/4\left( \frac{y^4}{x^3 z^{1/2}} \right)^{1/2} = \frac{y^2}{x^{3/2} z^{1/4}}

Correct Answer:

Looking at the answer choices, the correct option is:

(y9x3z3)1/2\boxed{\left( \frac{y^9}{x^3 z^3} \right)^{1/2}}

This matches the structure of the simplified result.


Would you like further details or clarifications?

Here are some related questions:

  1. How do you simplify exponents involving square roots?
  2. What is the rule for multiplying terms with the same base?
  3. How do you handle negative exponents in division?
  4. Why is z1/2z^{-1/2} expressed as a square root?
  5. Can you apply this method to expressions with cube roots?

Tip: Always combine terms with the same base by adding or subtracting their exponents when multiplying or dividing.

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Math Problem Analysis

Mathematical Concepts

Exponent Rules
Square Roots
Algebraic Expressions
Simplification

Formulas

Square root of a term: \( \sqrt{a^n} = a^{n/2} \)
Exponent rules: \( a^m \cdot a^n = a^{m+n} \), \( \frac{a^m}{a^n} = a^{m-n} \)

Theorems

Laws of Exponents
Multiplication and Division of Terms with the Same Base

Suitable Grade Level

Grades 10-12