Math Problem Statement

6a^-1x5a/(3a^3)^0

Solution

Let's break down and simplify the expression:

6a1×5a÷(3a3)06a^{-1} \times 5a \div (3a^3)^0

Step 1: Simplify the exponent in the denominator

Any term raised to the power of zero is equal to 1. So,

(3a3)0=1(3a^3)^0 = 1

Thus, the expression becomes:

6a1×5a÷1=6a1×5a6a^{-1} \times 5a \div 1 = 6a^{-1} \times 5a

Step 2: Simplify the multiplication of terms

Now, multiply the constants and handle the powers of aa.

6×5=306 \times 5 = 30

For the powers of aa, use the rule of exponents: a1×a1=a1+1=a0a^{-1} \times a^1 = a^{-1 + 1} = a^0.

Since a0=1a^0 = 1, the entire expression simplifies to:

30×1=3030 \times 1 = 30

Final Answer:

3030

Let me know if you would like further clarification or have any questions! Here are some related problems you might want to try:

  1. Simplify 7a2×2a37a^{-2} \times 2a^3.
  2. What is (4b1×5b2)÷b3(4b^{-1} \times 5b^2) \div b^3?
  3. Simplify 8x2×x5÷x28x^{-2} \times x^5 \div x^2.
  4. Find the value of 9a3×a2×a19a^{-3} \times a^2 \times a^1.
  5. Simplify (2c3)0×4c2(2c^3)^0 \times 4c^2.

Tip: When multiplying terms with the same base, simply add the exponents!

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Math Problem Analysis

Mathematical Concepts

Exponents
Multiplication of algebraic terms
Exponent rules

Formulas

Any term raised to the power of zero equals 1: a^0 = 1
Multiplication rule for exponents: a^m * a^n = a^(m + n)

Theorems

Exponent Rule: Any base raised to the power of zero is 1
Exponent Addition: When multiplying terms with the same base, their exponents are added

Suitable Grade Level

Grades 8-10