To simplify \(\sqrt{8} \cdot \sqrt{2}\), we can combine the square roots:

\[
\sqrt{8} \cdot \sqrt{2} = \sqrt{8 \cdot 2} = \sqrt{16}
\]

Since \(\sqrt{16} = 4\), the simplified answer is:

\[
\sqrt{8} \cdot \sqrt{2} = 4
\]

Would you like a breakdown of each step or have any questions?

Here are five related questions for practice:
1. What is \(\sqrt{12} \cdot \sqrt{3}\)?
2. Simplify \(\sqrt{18} \cdot \sqrt{2}\).
3. If \(x = \sqrt{8}\) and \(y = \sqrt{2}\), what is \(x \cdot y\)?
4. How can you simplify \(\sqrt{50} \cdot \sqrt{2}\)?
5. Simplify \(\sqrt{6} \cdot \sqrt{3}\).

**Tip:** When multiplying square roots, you can combine them under a single square root as long as the terms are positive.

Understand how to simplify \(\sqrt{8} \cdot \sqrt{2}\) through multiplication of square roots, using the properties of square roots to combine radicals. Ideal for students in Grades 7-8 looking to strengthen their algebra and radical simplification skills.

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