To express $\sqrt{12}$ in its simplest radical form:

1. Begin by finding the prime factorization of 12: $12 = 2^2 \times 3$
2. Now break down $\sqrt{12}$ using these factors: $\sqrt{12} = \sqrt{2^2 \times 3}$
3. Since $2^2$ is a perfect square, you can take 2 out of the square root: $\sqrt{12} = 2\sqrt{3}$

Thus, the simplest radical form of $\sqrt{12}$ is $2\sqrt{3}$.

Would you like more details on this, or do you have any questions?

Here are 5 related questions:

1. How would you simplify $\sqrt{18}$?
2. What is the simplest radical form of $\sqrt{50}$?
3. How do you simplify $\sqrt{75}$?
4. Can you simplify $\sqrt{8}$ using the same method?
5. What is the value of $2\sqrt{3}$ to two decimal places?

Tip: When simplifying square roots, always look for the largest perfect square factor.