The expression \((s - 1)(s + 1)\) is a product of two binomials. This is a standard case of the **difference of squares** formula:

\[
(a - b)(a + b) = a^2 - b^2
\]

In this case, \(a = s\) and \(b = 1\). Applying the formula:

\[
(s - 1)(s + 1) = s^2 - 1^2 = s^2 - 1
\]

So, the simplified expression is:

\[
s^2 - 1
\]

Let me know if you'd like more details or further explanation!

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Here are 5 related questions to consider:
1. What happens when you apply the difference of squares to \((x - 2)(x + 2)\)?
2. How would you factor the expression \(x^2 - 9\) using the difference of squares?
3. Can you apply the difference of squares when the binomials are \((s - 1)(s - 1)\)?
4. What is the general rule for recognizing a difference of squares?
5. How can you factor \(4x^2 - 25\) using the difference of squares?

**Tip**: Always look for opportunities to apply special factorization formulas like difference of squares to simplify polynomial expressions quickly.

Learn how to simplify the expression (s - 1)(s + 1) using the difference of squares formula. This problem involves key algebraic concepts such as binomial products and the difference of squares. Suitable for students in Grades 8-10.

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