The image you uploaded shows a mathematical expression involving exponents and roots.

It appears to be:

$\left( x^2 \sqrt{y} \right) \left( \sqrt[3]{x^3 y^2 z} \right) \div \left( x^{5/3} y^{3/2} \right)$

To simplify this expression, let's break it down step by step:

Step 1: Simplify the exponents inside the square and cube roots.

1. $\sqrt{y} = y^{1/2}$
2. $\sqrt[3]{x^3 y^2 z} = x^{3/3} y^{2/3} z^{1/3} = x y^{2/3} z^{1/3}$

Step 2: Combine all terms in the numerator.

The numerator becomes: $x^2 \cdot y^{1/2} \cdot x \cdot y^{2/3} \cdot z^{1/3}$ Which simplifies to: $x^{2+1} y^{1/2 + 2/3} z^{1/3} = x^3 y^{7/6} z^{1/3}$

Step 3: Combine with the denominator.

Now, the denominator is: $x^{5/3} y^{3/2}$ So, the full expression is: $\frac{x^3 y^{7/6} z^{1/3}}{x^{5/3} y^{3/2}}$

Step 4: Simplify the expression by subtracting exponents for like terms.

For $x$: $x^3 \div x^{5/3} = x^{3 - 5/3} = x^{9/3 - 5/3} = x^{4/3}$

For $y$: $y^{7/6} \div y^{3/2} = y^{7/6 - 3/2} = y^{7/6 - 9/6} = y^{-2/6} = y^{-1/3}$

For $z$, since there's no $z$ in the denominator: $z^{1/3}$

Final Simplified Expression:

The simplified form of the expression is: $x^{4/3} y^{-1/3} z^{1/3}$

Would you like to go over the steps in more detail or need further clarification?