Simplify forty eight divided by eight plus thirteen times t

To simplify the expression \( \frac{48}{8} + 13 \times t \):

1. First, perform the division:  
   \( \frac{48}{8} = 6 \).

2. Then, the expression becomes:  
   \( 6 + 13 \times t \).

Thus, the simplified expression is:

\[
6 + 13t
\]

Would you like more details, or do you have any questions?

Here are 8 related questions to expand your understanding:

1. How do you simplify expressions involving multiple operations?
2. What is the order of operations in algebra?
3. How would the expression change if it was \( \frac{48 + 8}{13 \times t} \)?
4. How do you handle variables in algebraic expressions?
5. What happens if you change the addition to subtraction in the expression \( 6 + 13t \)?
6. Can you solve the expression \( 6 + 13t = 0 \) for \( t \)?
7. How would the result differ if the multiplication was done first in \( 13 \times t \) before dividing 48 by 8?
8. How does the distributive property apply to expressions like \( 6 + 13t \)?

**Tip:** Always remember to follow the order of operations (PEMDAS: Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right)) when simplifying expressions.

Learn how to simplify the expression 48 divided by 8 plus 13 times t step-by-step. This problem involves arithmetic and algebraic operations, suitable for students in Grades 6-8.

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