Math Problem Statement

Simplify the expression involving the fifth root and square root of p: \( \sqrt[5]{p^2 \cdot \sqrt{p}} \).

Solution

The expression in the image is:

p2p5\sqrt[5]{p^2 \cdot \sqrt{p}}

Let me simplify it step by step.

  1. The inner square root p\sqrt{p} is equivalent to p1/2p^{1/2}, so the expression becomes: p2p1/25\sqrt[5]{p^2 \cdot p^{1/2}}

  2. Using the property of exponents aman=am+na^m \cdot a^n = a^{m+n}, combine the powers of pp: p2p1/2=p2+1/2=p5/2p^2 \cdot p^{1/2} = p^{2 + 1/2} = p^{5/2}

  3. Now, you have the fifth root of p5/2p^{5/2}: p5/25=p(5/2)(1/5)=p1/2\sqrt[5]{p^{5/2}} = p^{(5/2) \cdot (1/5)} = p^{1/2}

  4. p1/2p^{1/2} is the same as p\sqrt{p}.

Thus, the simplified expression is:

p\sqrt{p}

Let me know if you need further details or have any questions!

Here are 5 related questions:

  1. How do you simplify nested radicals?
  2. What are the properties of exponents when dealing with roots?
  3. How would you simplify p4p3\sqrt[3]{p^4 \cdot \sqrt{p}}?
  4. Can you explain why p\sqrt{p} is the same as p1/2p^{1/2}?
  5. How can you express higher roots in terms of fractional exponents?

Tip: Always simplify exponents first when dealing with radicals; it can make solving the expression easier!

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Math Problem Analysis

Mathematical Concepts

Exponents
Radicals
Algebraic Simplification

Formulas

a^m \cdot a^n = a^{m+n}
\sqrt[n]{a^m} = a^{m/n}

Theorems

Exponentiation Rules
Radical Properties

Suitable Grade Level

Grades 10-12