Math Problem Statement

π‘₯(2π‘₯3

βˆ’ 3π‘₯)

Solution

To simplify the expression x(2x3βˆ’3x)x(2x^3 - 3x), we need to distribute the xx to each term inside the parentheses:

  1. Distribute xx to 2x32x^3:

xβ‹…2x3=2x4x \cdot 2x^3 = 2x^4

  1. Distribute xx to βˆ’3x-3x:

xβ‹…(βˆ’3x)=βˆ’3x2x \cdot (-3x) = -3x^2

Now, combine these results:

2x4βˆ’3x22x^4 - 3x^2

So, the simplified expression is:

2x4βˆ’3x22x^4 - 3x^2

Would you like more details or have any questions about this solution?

Here are some more questions you might want to explore:

  1. How do you factorize polynomials?
  2. What are the rules for multiplying polynomials?
  3. How do you simplify algebraic expressions?
  4. What is the difference between polynomial and rational expressions?
  5. How do you solve polynomial equations?

Tip: When simplifying expressions, always look for common factors and apply the distributive property correctly.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Distributive Property
Polynomials

Formulas

-

Theorems

-

Suitable Grade Level

Grades 7-9