Math Problem Statement

\left(w^{3}\right)^{8}\cdot\left(w^{5}\right)^{5}

Solution

To simplify the expression (w3)8(w5)5(w^3)^8 \cdot (w^5)^5, we use the following exponentiation rules:

  1. Power of a power rule: (am)n=amn(a^m)^n = a^{m \cdot n}.
  2. Product of powers rule: aman=am+na^m \cdot a^n = a^{m+n}.

Step-by-step solution:

  1. Apply the power of a power rule to each term: (w3)8=w38=w24(w^3)^8 = w^{3 \cdot 8} = w^{24} (w5)5=w55=w25(w^5)^5 = w^{5 \cdot 5} = w^{25}

  2. Now the expression becomes: w24w25w^{24} \cdot w^{25}

  3. Apply the product of powers rule: w24w25=w24+25=w49w^{24} \cdot w^{25} = w^{24 + 25} = w^{49}

Final Answer:

w49w^{49}

Would you like a detailed explanation of the rules used or have any follow-up questions?


Here are five related questions for further exploration:

  1. How do you simplify expressions with negative exponents, such as (w3)4(w^{-3})^4?
  2. What happens if you divide powers with the same base, e.g., w10w6\frac{w^{10}}{w^6}?
  3. Can you explain the difference between power of a product and power of a quotient?
  4. How do the rules for fractional exponents work, such as (w1/2)4(w^{1/2})^4?
  5. What is the general formula for simplifying (am)n(ap)q(a^m)^n \cdot (a^p)^q?

Tip: Always ensure bases are the same before applying exponent rules. This avoids errors in simplification!

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Math Problem Analysis

Mathematical Concepts

Exponents
Simplification of Powers
Algebra

Formulas

Power of a power rule: (a^m)^n = a^(m⋅n)
Product of powers rule: a^m ⋅ a^n = a^(m+n)

Theorems

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Suitable Grade Level

Grades 8-10