Let's simplify the given expression:

$\frac{8x^8 y^8}{4y^7}$

Step 1: Simplify the coefficients.

The coefficients are $\frac{8}{4} = 2$.

Step 2: Simplify the variables.

• For the $x$ terms: We only have $x^8$ in the numerator, so it stays as $x^8$.
• For the $y$ terms: Use the property of exponents $\frac{y^8}{y^7} = y^{8-7} = y^1 = y$.

Final Simplified Expression:

$2x^8 y$

So, the simplified form of the expression is:

$2x^8 y$

Would you like any further details or have any questions?

Here are 5 related questions for practice:

1. How would you simplify $\frac{12x^6y^9}{3x^2y^3}$?
2. What is the result of $\frac{5x^7}{x^3}$?
3. How can you simplify $\frac{6a^4b^5}{2a^2b^3}$?
4. How does exponent subtraction work when dividing terms with the same base?
5. What is the value of $\frac{x^5}{x^5}$?

Tip: When dividing like terms, subtract the exponents of matching bases.