Math Problem Statement

Simplify the expression 5pq(p^2 - q^2) ÷ 2p(p + q).

Solution

The expression provided in the image is:

5pq(p2q2)÷2p(p+q)5pq(p^2 - q^2) \div 2p(p + q)

Let's simplify this step by step.


Step 1: Factorize p2q2p^2 - q^2

The term p2q2p^2 - q^2 is a difference of squares, so we can write: p2q2=(pq)(p+q)p^2 - q^2 = (p - q)(p + q)

Substituting this into the expression, we get: 5pq(pq)(p+q)2p(p+q)\frac{5pq \cdot (p - q)(p + q)}{2p \cdot (p + q)}


Step 2: Cancel common terms

The term p+qp + q appears in both the numerator and denominator, so it cancels out: 5pq(pq)2p\frac{5pq \cdot (p - q)}{2p}


Step 3: Simplify further

The pp in the denominator cancels with the pp in 5pq5pq in the numerator: 5q(pq)2\frac{5q \cdot (p - q)}{2}


Final Simplified Expression:

5q(pq)2\frac{5q(p - q)}{2}

Would you like a detailed explanation of any step? Let me know!


Here are 5 related questions to deepen your understanding:

  1. How do you factorize higher-order polynomials, like x3y3x^3 - y^3?
  2. What are some other cases where terms cancel out during simplification?
  3. How does the difference of squares formula apply to other algebraic problems?
  4. What is the importance of factoring in simplifying algebraic expressions?
  5. How can you check your final simplified answer for correctness?

Tip:

When simplifying fractions, always look for common factors in the numerator and denominator to cancel terms efficiently.

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Math Problem Analysis

Mathematical Concepts

Algebra
Simplification of Expressions
Difference of Squares

Formulas

p^2 - q^2 = (p - q)(p + q)

Theorems

Difference of Squares Theorem

Suitable Grade Level

Grades 8-10