Math Problem Statement

(X^3y^4)^2

Solution

To simplify the expression (x3y4)2(x^3 y^4)^2, follow these steps:

  1. Apply the power rule for exponents: (ambn)p=ampbnp(a^m b^n)^p = a^{m \cdot p} b^{n \cdot p}.
  2. Distribute the exponent 22 to both x3x^3 and y4y^4.

(x3y4)2=(x3)2(y4)2(x^3 y^4)^2 = (x^3)^2 (y^4)^2

Now apply the power of a power rule, which states that (am)p=amp(a^m)^p = a^{m \cdot p}:

(x3)2=x32=x6(x^3)^2 = x^{3 \cdot 2} = x^6 (y4)2=y42=y8(y^4)^2 = y^{4 \cdot 2} = y^8

Thus, the simplified expression is:

x6y8x^6 y^8

Would you like more details or have any further questions?

Here are five related questions:

  1. How do you simplify (a5b2)3(a^5 b^2)^3?
  2. What is the general rule for powers of a product?
  3. How would you simplify (x2y3z)4(x^2 y^3 z)^4?
  4. Can you explain the difference between (xm)n(x^m)^n and xm+nx^{m+n}?
  5. How do you handle negative exponents in similar expressions?

Tip: When raising an expression to a power, always apply the exponent to each base inside the parentheses.

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Math Problem Analysis

Mathematical Concepts

Exponentiation
Algebra

Formulas

(a^m b^n)^p = a^{m \cdot p} b^{n \cdot p}
(a^m)^p = a^{m \cdot p}

Theorems

Exponentiation Rules
Power of a Power Rule

Suitable Grade Level

Grades 8-10