Math Problem Statement

Evaluate and simplify the following complex fraction.

[\Large\dfrac{ ~\frac {2}{3}~ }{ \frac{4}{-9}} = ]

Solution

To evaluate and simplify the given complex fraction, we'll start by rewriting it in a clearer form:

2349\Large \dfrac{\frac{2}{3}}{\frac{4}{-9}}

This fraction can be simplified by multiplying the numerator by the reciprocal of the denominator:

23×94\Large \dfrac{2}{3} \times \dfrac{-9}{4}

Now, multiply the fractions:

2×93×4=1812\Large \dfrac{2 \times -9}{3 \times 4} = \dfrac{-18}{12}

Next, simplify 1812\dfrac{-18}{12} by dividing both the numerator and the denominator by their greatest common divisor, which is 6:

18÷612÷6=32\Large \dfrac{-18 \div 6}{12 \div 6} = \dfrac{-3}{2}

So, the simplified result is:

32\Large \dfrac{-3}{2}

Would you like more details or have any questions? Here are some related questions to expand on this:

  1. How do you find the reciprocal of a fraction?
  2. What are the steps to simplify a complex fraction?
  3. How do you determine the greatest common divisor of two numbers?
  4. What are some tips for multiplying fractions?
  5. How can complex fractions be simplified using other methods?

Tip: Always remember to check for the reciprocal when dividing by a fraction!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Fractions
Reciprocal
Multiplication of Fractions
Simplification

Formulas

\dfrac{a}{b} \div \dfrac{c}{d} = \dfrac{a}{b} \times \dfrac{d}{c}
Simplification of Fractions: \dfrac{p}{q} \div GCD(p, q)

Theorems

Multiplication of fractions involves multiplying numerators and denominators
Simplifying fractions using the greatest common divisor (GCD)

Suitable Grade Level

Grades 6-8